Ohm's Law Calculator

Calculate voltage, current, resistance, and power using Ohm's Law. Enter any two values — get all four electrical quantities instantly.

A
Ω

Enter your values above to see the results.

Tips & Notes

  • Ohm's Law applies to resistive (ohmic) components at constant temperature. Non-ohmic devices like diodes and LEDs do not follow a linear V-I relationship — their resistance changes with operating conditions.
  • Power dissipates as heat in resistors: P = I²R. A 100 Ω resistor carrying 0.1 A dissipates P = 0.01 × 100 = 1 W. Always use resistors rated at least 2× the calculated power to avoid overheating.
  • In series circuits: R_total = R₁ + R₂ + ... and the same current flows through all components. In parallel: 1/R_total = 1/R₁ + 1/R₂ + ... and the same voltage appears across all branches.
  • Real voltage sources have internal resistance. A 12 V battery under heavy load may deliver only 11.2 V due to internal resistance voltage drop. This is why battery voltage sags when starting a car engine.
  • For AC circuits, use RMS values: V_RMS = V_peak / √2 ≈ 0.707 × V_peak. Household 120 V AC means 120 V RMS, with a peak of 170 V. Ohm's Law works normally with RMS values for resistive loads.

Common Mistakes

  • Mixing AC peak and RMS values — Ohm's Law gives correct results only when both voltage and current are expressed in the same form. Using peak voltage with RMS current (or vice versa) gives wrong power by a factor of √2.
  • Ignoring wire resistance in high-current circuits — even short wire runs have resistance. A 1 m AWG 18 copper wire (0.021 Ω/m) carrying 10 A drops 0.21 V and dissipates 2.1 W. This matters in automotive and power electronics.
  • Choosing resistor value without checking power rating — calculating R = V/I without also calculating P = I²R often leads to undersized resistors that overheat. Always verify power dissipation.
  • Applying Ohm's Law to non-linear components — diodes, LEDs, transistors, and Zener diodes have non-constant resistance. Use their characteristic curves or datasheet values, not simple V/I calculations.
  • Forgetting to account for component tolerances — a resistor marked 1 kΩ may actually be 950–1,050 Ω (5% tolerance). For precision circuits, calculate the effect of tolerance spread on voltage and current.

Ohm's Law Calculator Overview

Ohm's Law (V = IR) is the cornerstone of electrical engineering — the single equation that connects voltage, current, and resistance in every resistive circuit. Combined with the power formula P = VI, it provides complete characterization of DC electrical behavior.

Ohm's Law and power formulas:

V = I × R | I = V / R | R = V / I | P = V × I = I²R = V²/R
EX: 9 V battery, 470 Ω resistor → I = 9/470 = 19.1 mA → P = I²R = (0.0191)² × 470 = 172 mW. Use at minimum a 1/4 W rated resistor (250 mW). For 2× safety margin, use 1/2 W.
Series vs. parallel circuits:
Series: R_total = R₁ + R₂ | Parallel: R_total = (R₁ × R₂)/(R₁ + R₂) | n equal resistors parallel: R/n
EX: 100 Ω + 220 Ω + 330 Ω in series → R = 650 Ω. Same three in parallel: 1/R = 1/100+1/220+1/330 = 0.01758 → R = 56.9 Ω. Parallel always lower than smallest individual value.
Ohm's Law — formula matrix:
FindKnown: V, IKnown: V, RKnown: I, R
Voltage (V)V = I × R
Current (I)I = V / R
Resistance (R)R = V / I
Power (P)P = V × IP = V² / RP = I² × R
Standard resistor power ratings:
RatingMax Current (100 Ω)Max Voltage (100 Ω)Typical Package
1/8 W35 mA3.5 VSMD 0402/0603
1/4 W50 mA5 VAxial, SMD 0805
1/2 W71 mA7.1 VAxial, SMD 1206
1 W100 mA10 VAxial or wirewound
5 W224 mA22.4 VWirewound, heatsink
Every electronic design calculation begins with Ohm's Law. Before placing any component, engineers calculate the current through it, verify power dissipation against the component rating, and check that voltage drops are within specification. The consequences of ignoring these calculations range from warm resistors and dim LEDs to fires and destroyed components — making V = IR the most practically important equation in electronics.

Frequently Asked Questions

Ohm's Law: V = I × R. Rearranged: I = V / R, R = V / I. Enter any two known values to find the third. Example: 12 V supply, 330 Ω resistor → I = 12 / 330 = 36.4 mA. Power: P = V × I = 12 × 0.0364 = 0.436 W. Or P = V²/R = 144/330 = 0.436 W, or P = I²R = 0.0364² × 330 = 0.436 W. All three power formulas give the same result — choose the one using your known values.

Power can be calculated four ways: P = V × I (most direct, use when you know voltage and current); P = I² × R (use when you know current and resistance — common for calculating resistor heating); P = V² / R (use when you know voltage and resistance); P = V² × G (using conductance G = 1/R, useful for parallel analysis). Example: 5 V across a 68 Ω resistor: I = 5/68 = 73.5 mA; P = 5 × 0.0735 = 367 mW; verify P = 25/68 = 367 mW. Use a 1/2 W rated resistor.

Series: R_total = R₁ + R₂ + R₃. Same current flows through each resistor; voltages add. Parallel: 1/R_total = 1/R₁ + 1/R₂ + 1/R₃. Same voltage across each; currents add. Two resistors in parallel: R_total = (R₁ × R₂) / (R₁ + R₂). Example: 100 Ω and 150 Ω in parallel → R_total = (100 × 150)/(100 + 150) = 15,000/250 = 60 Ω. With 12 V supply: I_total = 12/60 = 200 mA total (120 mA through 100 Ω + 80 mA through 150 Ω = 200 mA).

Current-limiting resistor for LED: LED needs 20 mA, supply 5 V, LED forward voltage 2.1 V → R = (5 − 2.1) / 0.020 = 145 Ω → use 150 Ω standard. Power dissipated = (5−2.1) × 0.020 = 58 mW. Transistor base resistor: 5 V logic, want 1 mA base current, V_BE = 0.7 V → R = (5 − 0.7) / 0.001 = 4,300 Ω → use 4.7 kΩ. Voltage divider: 10 V in, want 3.3 V out → choose R1 = 10 kΩ, R2 = (3.3 × 10,000) / (10 − 3.3) = 4,925 Ω → use 4.7 kΩ. Ohm's Law is used in every analog circuit design step.

For DC circuits, V = IR applies directly. For AC circuits with reactive components (capacitors, inductors), the relationship becomes V = I × Z where Z is impedance — a complex number combining resistance R and reactance X. Capacitive reactance: X_C = 1/(2πfC). Inductive reactance: X_L = 2πfL. Total impedance: Z = √(R² + X²). For a 100 Ω resistor in series with a 10 mH inductor at 1 kHz: X_L = 2π × 1000 × 0.01 = 62.8 Ω → Z = √(100² + 62.8²) = 118.2 Ω. The current is 18.2% lower than in a purely resistive circuit.

Voltage: set to DC V (or AC V for mains), connect red probe to higher potential point, black to lower/ground. Connect in parallel with the component. Never insert a voltage-measuring multimeter in series — it will short the circuit. Current: set to A or mA, break the circuit wire, and insert the multimeter in series so current flows through it. Resistance: power the circuit off completely, disconnect at least one leg of the component, set to Ω, probe both ends. Safety: never measure resistance on live circuits, never exceed the meter's input voltage rating, use properly rated probes for mains voltage work.